# 自定义类型（custom）

> 原文：[Creating a Basic Custom Schema Type](http://mongoosejs.com/docs/customschematypes.html)\
> 翻译：小虾米（QQ:509129）

## 创建一个基本的自定义模式类型

Mongoose 4.4.0的新特征：Mongoose支持自定义类型。在你达到一个自定义的类型，然而，知道一个自定义的类型是过度对大多数用例。你可以用最基本的任务 [custom getters/setters](http://mongoosejs.com/docs/2.7.x/docs/getters-setters.html)，虚函数（[virtuals](http://mongoosejs.com/docs/guide.html#virtuals)）和[单一的嵌入式文档](http://mongoosejs.com/docs/subdocs.html#single-embedded)。

让我们看看一个基本schema类型看一个例子：一个字节的整数。创建一个新的schema类型，你需要继承`mongoose.SchemaType`并且将相应的属性添加到`mongoose.Schema.Types`。你需要实现一个方法是`cast()`方法。

```javascript
 function Int8(key, options) {
      mongoose.SchemaType.call(this, key, options, 'Int8');
    }
    Int8.prototype = Object.create(mongoose.SchemaType.prototype);

    // `cast()` takes a parameter that can be anything. You need to
    // validate the provided `val` and throw a `CastError` if you
    // can't convert it.
    Int8.prototype.cast = function(val) {
      var _val = Number(val);
      if (isNaN(_val)) {
        throw new Error('Int8: ' + val + ' is not a number');
      }
      _val = Math.round(_val);
      if (_val < -0x80 || _val > 0x7F) {
        throw new Error('Int8: ' + val +
          ' is outside of the range of valid 8-bit ints');
      }
      return _val;
    };

    // Don't forget to add `Int8` to the type registry
    mongoose.Schema.Types.Int8 = Int8;

    var testSchema = new Schema({ test: Int8 });
    var Test = mongoose.model('Test', testSchema);

    var t = new Test();
    t.test = 'abc';
    assert.ok(t.validateSync());
    assert.equal(t.validateSync().errors['test'].name, 'CastError');
    assert.equal(t.validateSync().errors['test'].message,
      'Cast to Int8 failed for value "abc" at path "test"');
    assert.equal(t.validateSync().errors['test'].reason.message,
      'Int8: abc is not a number');
```


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